What is Neon Number in Java

In Java, a “neon number” is not a standard or built-in concept. However, I can provide information on what a neon number is in mathematics, and you can implement a Java program to check whether a given number is a neon number.

A neon number (also known as a pseudoperfect number) is a number where the sum of the digits of its square is equal to the original number itself.

For example, let’s consider the number 9. Its square is 81, and the sum of its digits (8 + 1) equals 9, which is the original number. Therefore, 9 is a neon number.

To determine if a given number is a neon number in Java, you can follow these steps:

1. Obtain the number from the user or any other source.
2. Square the number.
3. Calculate the sum of the digits of the squared number.
4. Compare the sum with the original number.
5. If they are equal, then the number is a neon number; otherwise, it is not.

Here’s an example Java code snippet that checks if a number is a neon number:

import java.util.Scanner;

public class NeonNumber {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        System.out.print("Enter a number: ");
        int number = scanner.nextInt();
        
        int square = number * number;
        int sum = 0;
        
        // Calculate the sum of the digits of the squared number
        while (square > 0) {
            sum += square % 10;
            square /= 10;
        }
        
        // Compare the sum with the original number
        if (sum == number) {
            System.out.println(number + " is a neon number.");
        } else {
            System.out.println(number + " is not a neon number.");
        }
        
        scanner.close();
    }
}

In this code, we use the Scanner class to read the number input from the user. Then, we calculate the square of the number and find the sum of its digits using a loop. Finally, we compare the sum with the original number to determine if it is a neon number or not.